Bull in a China Shop

E

EricBess

Guest
Just picked up a new game called "Bull in a China Shop". It's basically a card game with a bit of setup, but it seems like it would be very easy to play online with very little moderation.

Here's how it works. There are 40 pieces of "China" to be purchased, each costs a "money". China comes in 3 colors - red, blue, and green, and various numeric values ranging from 3 to 8.

You get more money by selecting a "bull" card, which may or may not be detremental to your china and/or the china of other players. There are a couple different types of bull cards. Most destroy specific colors of china. For example, "a red and a green", or "2 blue". There are a few that destroy "any 2". When you take one of these bulls, you must destroy your own corresponding china, if you have any.

There are also bulls that destroy "all red" or "all 4/6/8". When you take those bulls, everyone loses all china of the specified type.

Everyone starts the game with 2 china (a 3 and a 4 of different colors), one money, and a "pass".

On your turn, you can do one of three things:

Buy china - You can only do this if you have money.
Take a bull - This gives you a money. You can only do this if you don't already have 2 money.
Pass - You can do this at any time, but you only get 1 pass during the entire game.

At the beginning of the game, 5 pieces of china are dealt face up and 5 bulls. That is what everyone picks from. At the end of the turn when the last piece of china has been taken, 5 more are dealt out. Same with the bulls, when they are depleted.

The bull deck may eventually be reshuffled. When the last china has been taken, the game ends.

There are 4 points during the game when scores are taken. They are after each group of 10 china (every other deal of 5). Each player scores their own china by adding up the following:

- The highest card they have of each color
- The lowest card they have of each color
- The total of any 1 color
- The total of all of their china.

That's everything. The nice thing here is that the moderator only needs to get involved when more cards need to be dealt, which only happens occassionally. The box says it plays with 3-5 players. I could moderate. I could probably play as well if everyone trusts me not to stack the deck in my favor, but if 5 others want to play, I'm good with just moderating.

Any interest?
 
T

train

Guest
I'm needing some help on this...

the cards remain "in-sight" and when a bull destoys all of one color - what happens to them?...
 
E

EricBess

Guest
Okay, if train has the question, probably other people do to, so we'll walk through an example, using Spiderman, train, and Melkor.

Spiderman: red 4; blue 3; pass; money
Melkor: green 4; red 3; pass; money
train: blue 4; green 3; pass; money

china: green 3, red 7, green 4, red 7, blue 4
bulls: any 2, all green, red & green, one of each, blue & green

Spiderman goes first and spends his money to take a red 7.
Melkor takes the other red 7.
train decides to bide his time and since he doesn't have red china and the green is going to get destroyed by the "all green" bull eventually anyway, he takes the red & green bull, destroying his red china.

The game would then look like this:

Spiderman: red 4, 7; blue 3; pass
Melkor: green 4; red 3, 7; pass
train: blue 4; pass; money x 2

china: green 3, green 4, blue 4
bulls: any 2, all green, one of each, blue & green

Clearly, each player would post an update, but for purposes of the example...

If we ever ran out of china or bulls, I would post 5 new ones.

train - you in? If no one else gets in, do you guys mind if I play also?
 
E

EricBess

Guest
Okay, good to go. I'm going to assume train wants in. If he doesn't, I'll take over his spot.

Here is the starting list and it will also be turn order:

train: Red: 3; Green: 4; Money; Pass
Spiderman: Blue: 3; Red: 4; Money; Pass
Mooseman: Blue: 4; Green: 3; Money; Pass
Melkor: Red: 4; Green: 3; Money; Pass
Ransac: Blue: 4; Red: 3; Money; Pass

China: Blue 4, Blue 7, Red 7, Green 6, Green 7
Bulls: 2 Blue, 2 Green, All Blue, 2 any, All Red

Okay, that's the setup. train - looks like you are up first.
 

Spiderman

Administrator
Staff member
Okay, wait, in the example, Melkor and I still keep our 7's even though the red China bull destroyed them? I thought we lose them? What's the purpose in keeping the numbers after the bull has destroyed the color?
 
E

EricBess

Guest
Only the bulls that destroy "all" affect other players.

When train took the "Red & Green" bull, only he needed to destroy one red and one green china. Since he didn't have a red china, he just ignored that and only had to destroy his green china.
 

Spiderman

Administrator
Staff member
Oh, I see what happened. You have a comma between the different numbers within the colors of the china, where a semi-colon separates the colors. I get it.
 
E

EricBess

Guest
If it's easier to see, we can write them out.

I don't know if train is coming back or not...we should get this started, so I'll play for train for now until we here definitively if he's planning on playing or not. I'll take the 2 blue bull:

train: Red: 3; Green: 4; Money x 2; Pass
Spiderman: Blue: 3; Red: 4; Money; Pass
Mooseman: Blue: 4; Green: 3; Money; Pass
Melkor: Red: 4; Green: 3; Money; Pass
Ransac: Blue: 4; Red: 3; Money; Pass

China: Blue 4, Blue 7, Red 7, Green 6, Green 7
Bulls: 2 Green, All Blue, 2 any, All Red
 

Spiderman

Administrator
Staff member
I'll pay to get the Blue 7

train: Red: 3; Green: 4; Money x 2; Pass
Spiderman: Blue: 3; Blue: 7; Red: 4; Pass
Mooseman: Blue: 4; Green: 3; Money; Pass
Melkor: Red: 4; Green: 3; Money; Pass
Ransac: Blue: 4; Red: 3; Money; Pass

China: Blue 4, Red 7, Green 6, Green 7
Bulls: 2 Green, All Blue, 2 any, All Red
 

Spiderman

Administrator
Staff member
Update:

train: Red: 3; Green: 4; Money x 2; Pass
Spiderman: Blue: 3; Blue: 7; Red: 4; Pass
Mooseman: Blue: 4; Green: 3; Money x 2; Pass
Melkor: Red: 4; Green: 3; Money; Pass
Ransac: Blue: 4; Red: 3; Money; Pass

China: Blue 4, Red 7, Green 6, Green 7
Bulls: 2 Green, All Blue, 2 any
 

Mooseman

Isengar Tussle
EricBess said:
Only the bulls that destroy "all" affect other players.
Shouldn't this be the update for an "All Red" bull

train: Green: 4; Money x 2; Pass
Spiderman: Blue: 3; Blue: 7; Red: 4; Pass
Mooseman: Blue: 4; Green: 3; Money x 2; Pass
Melkor:Green: 3; Money; Pass
Ransac: Blue: 4; Money; Pass

China: Blue 4, Red 7, Green 6, Green 7
Bulls: 2 Green, All Blue, 2 any
 
E

EricBess

Guest
Yes. And you missed one...

train : Green 4; Money x 2; Pass
Spiderman : Blue 3; Blue 7; Pass
Mooseman : Blue 4; Green 3; Money x 2; Pass
Melkor :Green 3; Money; Pass
Ransac : Blue 4; Money; Pass

China: Blue 4, Red 7, Green 6, Green 7
Bulls: 2 Green, All Blue, 2 any
 

Melkor

Well-known member
I'll take the Red 7

train: Green 4; Money x 2; Pass
Spiderman: Blue 3; Blue 7; Pass
Mooseman: Blue 4; Green 3; Money x 2; Pass
Melkor:Green 3; Red 7; Pass
Ransac: Blue 4; Money; Pass

China: Blue 4, Green 6, Green 7
Bulls: 2 Green, All Blue, 2 any
 
Top